Exponential Growth & Decay Calculator
Calculate exponential growth, decay, half-life, and Newton's cooling.
Population Growth
Radioactive Decay
Half-Life
Newton\'s Cooling
Quick Examples
Exponential Models
Growth & Decay Formula
r > 0 for growth, r < 0 for decay
Half-Life Formula
T = half-life period
Newton's Law of Cooling
Common Applications
| Application | Model | Example |
|---|---|---|
| Population | Growth | Demographics |
| Radioactive | Decay | Carbon dating |
| Bacteria | Growth | Lab cultures |
| Drug elimination | Decay | Pharmacology |
| Cooling object | Cooling | Forensics |
Half-Life Examples
- Carbon-14: 5,730 years
- Uranium-238: 4.5 billion years
- Iodine-131: 8 days
- Caffeine: ~5 hours
What Is Exponential Growth?
Exponential growth happens when a quantity changes by a constant percentage each period, so the change itself keeps growing. A population rising 5% per year does not add the same number of people each year — it adds 5% of an ever-larger total. This compounding effect is what makes exponential curves start slowly and then climb steeply.
Discrete vs. Continuous Growth
Growth can be applied once per period (discrete) or at every instant (continuous). The calculator above uses the continuous model:
| Model | Formula | When to Use |
|---|---|---|
| Discrete (per period) | P(t) = P0(1 + r)t | Yearly interest, annual population counts |
| Continuous (every instant) | P(t) = P0ert | Bacteria, radioactive decay, physics models |
The two are linked: a discrete rate r per period equals a continuous rate k = ln(1 + r). For small rates they are nearly identical — 5% discrete becomes k = ln(1.05) ≈ 0.04879 continuous.
Worked growth example: A bacteria culture starts at 500 cells and grows continuously at 30% per hour. After 5 hours: P = 500 · e0.3 × 5 = 500 · e1.5 ≈ 500 × 4.4817 = 2,240.84 cells.
Doubling Time and the Rule of 72
Doubling time is how long a growing quantity takes to double. For continuous growth at rate r:
At 5% continuous growth, that is 0.6931/0.05 ≈ 13.86 years. The famous Rule of 72 gives a quick mental estimate: divide 72 by the percentage rate — 72/5 = 14.4 years, close to the exact discrete value of 14.21 years. The rule works because ln(2) ≈ 0.693, and 72 has many convenient divisors.
Exponential Decay and Half-Life
With a negative rate, the same formula describes exponential decay: quantities shrink by a fixed percentage each period. Decay is usually expressed through the half-life T — the time for half the substance to disappear:
Worked decay example: A sample of 100 g has a half-life of 5 days. After 15 days (three half-lives): N = 100 · (1/2)3 = 100/8 = 12.5 g. After another 5 days only 6.25 g remains — decay never quite reaches zero.
Newton's Law of Cooling
A hot object cools toward the surrounding temperature at a rate proportional to the temperature difference:
Where Ta is the ambient temperature, T0 the initial temperature, and k the cooling constant. Worked example: Coffee at 90°C in a 20°C room with k = 0.05 per minute. After 10 minutes: T = 20 + 70 · e−0.5 ≈ 20 + 70(0.6065) = 62.5°C. The same formula models warming — a cold drink left in a warm room follows it in reverse.
Solving for the Rate or the Time
Logarithms unlock the other variables. From P = P0ert:
Worked example: An investment doubles in 10 years. What continuous rate does that imply? r = ln(2)/10 ≈ 0.0693 = 6.93% per year.
Real-World Applications
| Application | Model | Example |
|---|---|---|
| Population growth | Growth | A city growing 2% per year doubles in about 35 years |
| Radioactive decay | Half-life | Carbon-14 (half-life 5,730 years) dates ancient artifacts |
| Compound interest | Growth | Money at 7% doubles roughly every 10 years |
| Cooling and heating | Newton's law | Forensic cooling curves estimate time of death |
| Bacterial cultures | Growth | Lab cultures doubling every 20–30 minutes |
| Viral spread | Growth then decay | Early epidemic curves and their flattening |
Common Mistakes to Avoid
- Entering the rate as a percent in ert: The continuous formula needs the decimal — 5% is 0.05, not 5.
- Mixing discrete and continuous rates: 5% discrete ≠ 5% continuous; convert with k = ln(1 + r).
- Mismatched time units: A "per hour" rate needs time in hours, not days or years.
- Assuming exponential when it is linear: Fixed amounts per period are linear; fixed percentages are exponential.
- Forgetting decay never hits zero: Half-life models approach zero asymptotically — (1/2)n is never exactly 0.
Comparing Growth Rates
Small rate differences compound into large gaps. Discrete doubling times at several rates:
| Annual Rate | Doubling Time | Rule-of-72 Estimate |
|---|---|---|
| 3% | 23.45 years | 24.0 years |
| 5% | 14.21 years | 14.4 years |
| 7% | 10.24 years | 10.3 years |
| 10% | 7.27 years | 7.2 years |
Worked Example: Radioactive Dating
Carbon-14 has a half-life of 5,730 years. A sample containing 60% of its original carbon-14 is how old? Rearrange N = N0(1/2)t/T: t = T · ln(N/N0) / ln(1/2) = 5,730 × ln(0.6)/ln(0.5) ≈ 5,730 × 0.7370 ≈ 4,223 years. Check: (1/2)4223/5730 = (1/2)0.737 ≈ 0.60 ✓
Worked Example: Population Projection
A city of 2 million grows at 1.5% per year (discrete). In 20 years: P = 2 × (1.015)20 ≈ 2 × 1.3469 = 2.69 million. The same projection continuously uses k = ln(1.015) ≈ 0.01489: 2e0.01489 × 20 ≈ 2.69 million — the models agree to two decimals at small rates.
Beyond Pure Exponentials: The S-Curve
Real populations and markets rarely grow exponentially forever — limited resources bend the curve into an S-shape (logistic growth): fast growth at first, then a slowdown toward a carrying capacity. Exponential models are accurate for the early phase, which is exactly when most projections are made.
How Long to Grow Tenfold?
Doubling time generalizes to any multiple. The time to grow by a factor of m at continuous rate r is t = ln(m)/r. At 5% continuous growth, growing tenfold takes ln(10)/0.05 ≈ 46.05 years — a useful figure for long-range technology and investment projections.
Present Value: Discounting Backwards
Exponential math also runs in reverse. To have $50,000 in 15 years at 6% continuous growth, how much must you invest today? Rearrange P(t) = P0ert:
This "discounting" is how bonds are priced and how pension funds value future obligations — the present value of money falls exponentially the further out it sits.
Finding the Half-Life from Two Measurements
You do not need to know the half-life in advance. If a sample falls from 100 g to 70 g in 5 days, the decay constant is λ = −ln(0.7)/5 ≈ 0.071335 per day, and the half-life is T = ln(2)/λ ≈ 9.72 days. Check: (1/2)5/9.72 ≈ 0.70 ✓. Two data points are enough to characterize any exponential decay.